H2O 4 liquid is changed to 2x O2 gas delta u is equal to 2.1 kilo calorie deltas 20 calorie Kelvin at 300 Kelvin delta g is
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The change in Gibbs Free energy is given by
ΔH=ΔU+Δn
g
RT
where
ΔH is the enthalpy of the reaction
ΔS is the entropy of the reaction
and ΔU is the change in internal energy
Δn
g
is the (number of gaseous moles in product) - (number of gaseous moles in reactant)=2-0=2
R is the gas constant =2 cal
But,
ΔH=(2.1×10
3
)+(2×2×300)=3300cal
Hence,
ΔG=ΔH=TΔS
ΔG=3300−(300×20)
ΔG=−2700cal=−2.7cal
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