H₂O₂ → 2H⁺ + O₂ + 2e⁻ ; E° = –0.68 V. This equation
represents which of the following behaviour of H₂O₂.
(a) Reducing (b) Oxidising
(c) Acidic (d) Catalytic
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The behaviour of H2O2 will be reducing.
Option (A) is correct.
Explanation:
As we know that
Loss of electrons = Oxidation
In the above reaction electrons have been lost by H2O2. so H2O2 have been oxidized and another compound will be reduced.
So H2O2 will act as reducing agent.
H2O2 acts as reducing agent towards powerful oxidizing agent.
Thus the behaviour of H2O2 will be reducing.
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