Question

H₂O₂ ⟶ 2H⁺+ O₂ + 2e⁻;E° = - 0.68V.
The above equation represents which of the
following behaviour of H₂O₂ ?
(a) Reducing (b) Oxidising
(c) Acidic (d) Catalytic.

Answer 1

(d) Catalytic. ids ewf ergfff 4f 4

Answer 2

(b) Oxidising

Explanation:

H₂O₂ ----> 2H + O₂ + 2e⁻;E° = - 0.68V.

The above reaction exhibits the oxidising properties of H₂O₂. The elements lose electron here. So this is a oxidization reaction. H₂O₂ is the oxidising agent.

Option A is the answer.