Question

H2P2O7
Calculate oxidation number of Phosphorus

Answer 1

Answer:

+2+2x-14=0

2x=12

x=6

6 is the oxidation number of Phosphorus

Answer 2

The oxidation number of phosphorus is +6 in $H_{2} P_{2} O_{7}$. The total number of electrons that an atom acquires or loses to establish a chemical bond with another atom is known as the oxidation number, also known as the oxidation state.

Oxidation state:

• In chemistry, the term "oxidation state" (sometimes called "oxidation number") refers to the fictitious charge that an atom would have if all of its bonds to other atoms were fully ionic.
• It describes the degree of atom oxidation within a chemical compound.
• The oxidation state may be positive, negative, or zero in theory.
• The reaction of a substance with oxygen is referred to as "oxidation" by Antoine Lavoisier.

The oxidation number of Phosphorus in $H_{2} P_{2} O_{7}$:

• The oxidation number of Hydrogen is +1.
• and for Oxygen, it is -2.
• So now let's assume the oxidation number of phosphorus is x.
• 2x(+1) + 2x + 7(-2) = 0
• 2 + 2x - 14 = 0
• 2x - 12=0
• x = +6.

The oxidation number of phosphorus is +6 in $H_{2} P_{2} O_{7}$.

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