Question

H2s + 12 -->2HI + s which element oxidizing agent and reducing agent
1. l + s
2. l and H2s
3. S and l
4. H2s and s
5. other​

Answer 1

Answer:

I and S

Explanation:

The oxidation state of Hydrogen is +1 and Sulfur is -2 on reactant Side and iodine is 0 because it is in elemental form.In product side the oxidation number hydrogen iodine is +1 and -1 and Sulfur is 0 because it is in elemental form.

In product side the oxidation number hydrogen iodine is +1 and -1 and Sulfur is 0 because it is in elemental form.Iodine is reducing agent because it's oxidation number is getting reduced from 0 to -1 while the S has a increase in its oxidation number from -2 to 0 so it act as a oxidizing agent.

Answer 2

Answer:

3 is the correct answer

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