Chemistry, asked by rajenderCheema203, 1 year ago

H2S, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If the solubility of H2S in water at STP is 0.195 m, calculate Henry’s law constant.

Answers

Answered by kvnmurty
16
solubility = s = H * p
               = henry's constant * partial pressure of the gas above the solution
     => H = 0.195 moles / 1 atm

   this is the Henry's law constant for solubility of H2 S in water at STP.

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