Question

H2S, a toxic gas with rotten egg like smell, is used for the qualitative analysis. If
the solubility of H2S in water at STP is 0.195 m, calculate Henry's law constant.​

Answer 1

Answer:

According to Henry's law...

P = Kh x

Answer 2

given ,

the solubility of H2S in water at STP is 0.195m

》 0.195mol of H2S is dissolved in 1000g of water

now,

no. of moles of water= 1000/ 18

=55.55mol

now,

mole fraction of H2S=(0.195)/(0.195+55.55)

=0.0035

At STP,

pressure = 1 bar

according to henry's law,

p= (KH)x

KH= 1/0.0035

= 285 bar

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