H2S + Cr2O7^-2= Cr3+ + s + H₂O को आयन इलेक्ट्रॉन विधि द्वारा सन्तुलित कीजिये?
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Answer:
3H2S + Cr2O7^-2 + 8H+ --> 2Cr^+3 + 3S + 7H2O
Explanation:
Cr2O7^-2 -> Cr^+3 (Per atom change 3, total change 6)
To make oxidation = reduction, multiply 3 to oxidation subscript.
hope this will help you
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