Question

H2s initially at a pressure of 10 atm and a temperature of 800k dissociates as , 2H2S gives 2H2 + S2 at equilibrium the partial pressure of S2 vapour is 0.020 atm,thus Kp is

Answer 1

$\huge\underline\mathfrak\red{Solution}$

H2s initially at a pressure of 10 atm and a temperature of 800k dissociates as , 2H2S gives 2H2 + S2 at equilibrium the partial pressure of S2 vapour is 0.020 atm,thus Kp is.