h2s2o7 what is the oxidation of s2
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Answered by
1
2+2x-14=0
x=6 oxidation state
x=6 oxidation state
Answered by
3
Oxidation state =2*1+2x+7(-2)=0
2+2x-14=0
X=14-2/2
X=6
Oxidation state of s=+6
2+2x-14=0
X=14-2/2
X=6
Oxidation state of s=+6
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