Question

H2so4_9.8gm/250ml me normality find kro

Answer 1

•♠•♠• FOLLOW•♠•♠•

»»»»Given:

Volume of solution = 250 ml

pH of the solution = 0

We know,

pH = -log[H+]

0 =-log[H+]

Taking antilog

[H+] = 1 M

we know that,

Molaity of H2SO4 = 2Normality of H2SO4

Normality of H2SO4

equals space 1 half Molarity space of space straight H subscript 2 SO subscript 4

space equals 1 half cross times 1

equals space 0.5 space straight N

Normality of solution is 0.5 N