Question

H2SO4 + HBr gives rise to SO2 + Br2 + H2O
find oxidation
reduction
oxidising agent
reducing agent

Answer 1

oxidising agent is h2s
reducing agent is h2

Answer 2

Solution : The reaction is an oxidation reduction reaction (redox) reaction.

• Oxidation number of bromine is -1 so in oxidation reaction oxidation number of bromine increases to 0 . The reaction is $2 Br^{-1} -2e^{-1} - > 2Br^{0}$  , bromine is formed which is dark reddish brown fuming liquid.
• Oxidation number of Sulphur is +6 in reduction reaction oxidation number of Sulphur will decrease to 4 . The reaction is $S^{+6} +2e^{-} - > S^{+4}$,
• Here HBr hydrogen bromide is reducing agent . It is colorless gas with a sharp irritating odor, it is often used in aqueous solution
• Here $H_{2}SO_{4}$ sulfuric acid is oxidizing agent . It is clear colorless oily hygroscopic liquid.

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