Chemistry, asked by Rakshitha7247, 1 year ago

H₃BO₃ on heating up to 373 K yields:
(a) boric anhydride
(b) orthoboric acid
(c) metaboric acid
(d) tetraboric acid

Answers

Answered by saquib2603
1

Explanation:

Boric anhydride is obtained on heating H³BO³ upto 373

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Answered by tushargupta0691
0

Answer:

The chemical compound containing boron, oxygen, and hydrogen with the formula H₃BO₃ or B(OH)3 is known as boric acid, or more particularly orthoboric acid.

Explanation:

H₃BO₃ on heating up to 373 K yields metaboric acid.

The reaction is as follows below.

             H₃BO₃ + 373 K + heat → HBO₂ + H₂O

Three main processes are taken while heating boric acid.

Metaboric acid is produced when orthoboric acid is slightly heated to a temperature of around 370 Kelvin.

Tetra boric acid is produced when the metaboric acid is heated further at a relatively higher temperature and loses even more water.

Tetra boric acid undergoes additional water loss when exposed to red heat, which causes the formation of boron trioxide or borax.

Hence, the correct option is (c) metaboric acid.

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