Question

H3PO2 + Cr2O7

2- → H3PO4 + Cr3+ solve in acidic medium

Answer 1

Answer:

I would first write it conplety ionically

Explanation:

P02^3- +Cr207^2- ------->P04^3- +Cr3+

9×(P02^3- +2H20---–>P04^3-+4H++4e-)

4×(Cr207^2-+14H++9e- -----> 2Cr3++7H20)

9P02^3-+18H20---->9P04^3-+36H+36e-

4cr207^2-+56H++36e---->8Cr3++28H20

9P02^3-+4Cr207^2-+20H+ ----->9P04^3

-+8Cr3++10H20