Question

H3PO4 IS A TRIBASIC ACID AND ONE OF ITS SALT IS NaH2PO4 WHAT VOLUME OF 1 M NaOH SoLUTION SHOULD BE ADDED TO 12 g NaH2PO4 TO CONVERT IT INTO Na3PO4 ...

Answer 1

NaH2PO4 +2 NaOH →Na3PO4 + H2O
​Thus according to this reaction 1 mol of NaH2PO4 react with 2 mol of NaOH.
Molar mass of NaH2PO4​ = 120g/mol
Number of moles of ​ NaH2PO4​  in 12g = 12120= 0.1 mol
Thus number of moles of NaOH required for complete reaction to occur = 2×0.1 mol = 0.2 mol
 
Thus 0.2 mol NaOH is required for complete reaction.
Since molarity of NaOH is given to be 1 mol/L
This means volume of 1 mol NaOH = 1L
Thus volume of 0.2 mol NaOH = 1​×0.2 L = 0.2 L
                                             = 0.2​×1000 mL = 200 mL

Therefore 200 mL of 1 M NaOH should be added to 12 g NaH2PO4 to exactly convert it into Na3PO4.
 

Answer 2

Answer:200ml

Explanation: just equate the gram equivalents for the answer