हिट ऑफ जॉब इन 1 ग्राम ऑफ आइस मेल्ट एंड जीरो डिग्री सेल्सियस टू फॉर्म 1 ग्राम ऑफ वाटर एंड द सेम टेंपरेचर इज
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Answer:
Heat water can release =10×1×40
=400cal
Heat required by ice to melt =800cal[80×10]
∵ heat release is less than heat required
So, water left = ice melts + log of water
=
80
400
+10g
=15gm
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