हाउ मच हीट एनर्जी इज वेरी वेरी टुडे इज द टेंपरेचर ऑफ कीजिए वाटर पार्क एंट्री गेट सेल्सियस डिग्री सेल्सियस
vp403281:
halo
but I want the answer
400 kcal
Answers
Answered by
0
Explanation:
Answer
Given :
Mass =5kg
T
1
=20
∘
C,T
2
=100
∘
C
ΔT=100−20=80
∘
C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
Answered by
5
Answer:
Given :
Mass =5kg
T
1
=20
∘
C,T
2
=100
∘
C
ΔT=100−20=80
∘
C
Q=m×C×ΔT
where C= specific heat capacity of water
=4200J/(kgK)
Q=5×4200×80
=1680000 Joule.
=1680KJ
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