Question

हाउ टू फाइंड द एक्स in isosceles triangle​

Answer 1

Answer:

For finding an x in the isosceles triangle, you first need to know the properties of an isosceles triangle (It also depends on where the x is, next time, click a pic and send)

An Isosceles Triangle has the Following Properties:

1. It has two sides of equal length. In the above figure, sides AB and AC are of equal length ‘a’ unit.

2. The angles opposite to equal sides are equal in measure. In the above figure, ∠ B and ∠C are of equal measure.

3.The altitude from vertex A to the base BC is the perpendicular bisector of the base BC.

4. The altitude from vertex A to the base BC is the angle bisector of the vertex angle ∠ A.

5. The altitude from the vertex divides an isosceles triangle into two congruent right-angled triangles. In the above figure, triangle ADB and triangle ADC are congruent right-angled triangles.

6. The median drawn from vertex A will bisect BC at right angles.

7. The medians drawn from vertex B and vertex C will not bisect the opposite sides AB and AC.

8. Two isosceles triangles are always similar.

9. In the right angled isosceles triangle, one angle is a right angle (90 degrees) and the other two angles are both 45 degrees.

10. In the right angled isosceles triangle, the altitude on the hypotenuse is half the length of the hypotenuse.

11. In the right angled isosceles triangle, the centre of circumcircle lies on the hypotenuse and the radius of circumcircle is half the length of hypotenuse.

12. An isosceles triangle whose two equal sides length is ‘a’ unit and length of its base is ’b’ unit. Then,  

Area of isosceles triangle = $b/2\sqrt{a^{2} -b^{2} /4}$

Perimeter of isosceles triangle = 2a + b

Pls mark as brainliest lol, took a lot of time.