Question

Ha weak acid the pH of 0.1 M Ha solution is 2 what is the degree of dispersion​

Answer 1

Answer:

pH =3 =- log[H+].

[H+] = 1 × 10^-3 M

[H+] = alpha × concentration

alpha = [H+]/concentration

= 1×10^-3/0.1

degree of dissociation= 1×10^-2.

Further

Ka ~alpha^2× concentration.

=(1×10^-2)^2×0.1

= 1×10^-5.