habit of company bag contains 24 balls of which X are red 2x are white and blue a ball is selected at random. what is the probability of that it is
a) not red
b) white
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Answer:
(a) 5/6
(b) 1/3
Step-by-step explanation:
Number of red balls = x
Number of white balls = 2x
Number of blue balls = 3x
Total number of balls in the bag = 24
=> x + 2x + 3x = 24
=> 6x = 24
=> x = 4
Thus,
Number of red balls = 4
Number of white balls = 8
Number of blue balls = 12
(i) Not red :
Total balls n(S) = 24
Let A be the event of selecting a ball which is not red.
n(A) = 8 + 12 = 20
Required probability = n(A)/n(S)
= 20/24
= 5/6
(ii) White :
Let B be the event of selecting a white ball.
n(B) = 8
Required probability = n(B)/n(S)
= 8/24
= 1/3
Hope it helps!
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