Question

Had ajita scored 10 more marks in her mathematics test out of 30 marks nine times these marks would have been the square of a actual mark how many marks did she get?

Answer 1

Answer:

Let her actual marks be x.

9(x+10)=x^2

x^2-9x-90=0

x^2-15x+6x-90=0

x(x-15)+6(x-15)=0

(x+6) (x-15) =0

x = -6

x= 15

x can't be negative.

Hence, x=15 .

So, Ajita got 15 marks in her test.

Hope it helps.✌

Answer 2

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Let her actual marks be x.

9(x+10)=x^2

x^2-9x-90=0

x^2-15x+6x-90=0

x(x-15)+6(x-15)=0

(x+6) (x-15) =0

x = -6

x= 15

x can't be negative.

Hence, x=15 .

So, Ajita got 15 marks in her test.