Question

Had Ajita scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

Answer 1

Answer:

Step-by-step explanation:

let ajita's orignal marks = x

9 (x+10)=x^2

×^2-9x-90

x^2-15x+6x-90

x (x-15)+6 (x-15)

(x+6)(x-15)=0

x= -6,15

-6 is not possible as marks can't be negative

So she got 15 marks in the exam

Answer 2

Answer:

$\tt\red{Answer-}$ $\tt\red{15}$

Step-by-step explanation:

Let her actual marks be ${x}$

Therefore,

⟹ 9(x+10) = x²

⟹ x²-9x-90 = 0

⟹ x²-15x+6x-90 = 0

⟹ x(x-15) +6(x-15) = 0

⟹ (x+6) (x-15) = 0

x = -6 or x = 15

Since x is the marks obtained, x ≠ -6.

Therefore, x = 15.

So, Ajita got 15 marks in her mathematics test.