Question

Had anita scored 10 marks out of 30 marks. 9 times the square of her actual marks,then what would be her mark out of the test?​

Answer 1

Answer:

Let the Mark's Scored By Anita be x .

According To the Given Condition

$9(x + 10) = x {}^{2}$

$x {}^{2} - 9x - 90 = 0$

$x {}^{2} - 15x + 6x - 90 = 0$

$x(x -15) + 6(x - 15) = 0$

mark obtained cannot be Negative

So x = 15

Mark's obtained by anita are 15

Answer 2

Answer:

Let her marks be x ...

so she scored ;

9 ( x + 10 ) = x^2

9x + 90 = x^2

x^2 - 9x - 90 = 0

x^2 -15x + 6x - 90 = 0

x ( x - 15 ) + 6 ( x - 15 ) = 0

( x - 15 ) ( x + 6 ) = 0

x = 15 and x = -6

since marks cannot be in negative so ;

x = 15

she scored 15 marks ...

hope it helps