Had Janya scored 10 more marks in mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test
Answers
Answer:
Step-by-step explanation:Brainly.in
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dhavaldomadiyalifest
Secondary School Math 8+4 pts
Q. Had Ajita scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?
Report by R4e9beraryanus 27.09.2016
Answers
hukam0685
Hukam0685★ Brainly Teacher ★
Answer: 15 Marks
Solution:
Let Ajita had scored x marks in the test of Mathematics.
According to the question,If she scored 10 marks more=> x+10
then 9 times of the marks = square of actual marks
So
9(10 + x) = {x}^{2} \\ \\ {x}^{2} - 9x - 90 = 0 \\ \\ {x}^{2} - 15x + 6x - 90 = 0 \\ \\ x(x - 15) + 6(x - 15) = 0 \\ \\ (x - 15)(x + 6) = 0 \\ \\ so \\ \\ x - 15 = 0 \\ \\ x = 15 \\ \\ or \\ \\ x + 6 = 0 \\ \\ x = - 6 \\ \\
Neglect x = -6
So, marks that Ajita scored are = 15
Verification:
= 9(15 + 10) \\ \\ = 9 \times 25 \\ \\ = > 225 = ( {15)}^{2} = 225 \\
Answer:
15 marks
Step-by-step explanation:
Let the marks scored by Janya = x
10 more marks => x + 10
9 times of these = 9(x + 10)
Square of actual marks = x²
According to the question,
9(x + 10) = x²
=> 9x + 90 = x²
=> x² - 9x - 90 = 0
=> x² - 15x + 6x - 90 = 0
=> x(x - 15) + 6(x - 15) = 0
=> x = -6 OR x = 15
As marks cannot be negative, x = 15
Answer: Janya scored 15 marks
Verification:
9*(15 + 10) = 9*25 = 225 = 15²
[Conditions set out in the problem are verified.]