Math, asked by ak2525, 10 months ago

Had Janya scored 10 more marks in mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test​

Answers

Answered by dhavaldomadiyalifest
4

Answer:

Step-by-step explanation:Brainly.in

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dhavaldomadiyalifest

Secondary School Math 8+4 pts

Q. Had Ajita scored 10 more marks in her mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test?

Report by R4e9beraryanus 27.09.2016

Answers

hukam0685

Hukam0685★ Brainly Teacher ★

Answer: 15 Marks

Solution:

Let Ajita had scored x marks in the test of Mathematics.

According to the question,If she scored 10 marks more=> x+10

then 9 times of the marks = square of actual marks

So

9(10 + x) = {x}^{2} \\ \\ {x}^{2} - 9x - 90 = 0 \\ \\ {x}^{2} - 15x + 6x - 90 = 0 \\ \\ x(x - 15) + 6(x - 15) = 0 \\ \\ (x - 15)(x + 6) = 0 \\ \\ so \\ \\ x - 15 = 0 \\ \\ x = 15 \\ \\ or \\ \\ x + 6 = 0 \\ \\ x = - 6 \\ \\

Neglect x = -6

So, marks that Ajita scored are = 15

Verification:

= 9(15 + 10) \\ \\ = 9 \times 25 \\ \\ = > 225 = ( {15)}^{2} = 225 \\

Answered by venupillai
6

Answer:

15 marks

Step-by-step explanation:

Let the marks scored by Janya = x

10 more marks => x + 10

9 times of these = 9(x + 10)

Square of actual marks = x²

According to the question,

9(x + 10) = x²

=> 9x + 90 = x²

=> x² - 9x - 90 = 0

=> x² - 15x + 6x - 90 = 0

=> x(x - 15) + 6(x - 15) = 0

=> x = -6 OR x = 15

As marks cannot be negative, x = 15

Answer: Janya scored 15 marks

Verification:

9*(15 + 10) = 9*25 = 225 = 15²

[Conditions set out in the problem are verified.]

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