had shreya scored 10 more marks in her test then she scored 5 times of these marks would have been the square of the actual marks how many marks did she get in test?
Answers
Answered by
5
5(10+x)=x^2
50+50x=x^2
x^2-50x-50=0
x= (-b +- _/b^2 - 4ac)÷2a
=(50 +- _/2500+4×1×50)÷2×1
=(50 +- _/2500+200)÷2
=(50 +- _/2700)÷2
=(50 +- 30_/3)/2
So, x=25 + 15_/3 or 25 - 15_/3
PLZ MARK IT AS BRAINLIEST..
50+50x=x^2
x^2-50x-50=0
x= (-b +- _/b^2 - 4ac)÷2a
=(50 +- _/2500+4×1×50)÷2×1
=(50 +- _/2500+200)÷2
=(50 +- _/2700)÷2
=(50 +- 30_/3)/2
So, x=25 + 15_/3 or 25 - 15_/3
PLZ MARK IT AS BRAINLIEST..
Answered by
2
Answer:
Let her actual marks = x
If she score 10 more then marks = x + 10
According to ques
5(x+10) = x2
=>5x +50 = x2
=> x2 - 5x - 50 = 0
=> x2 - 10x + 5x - 50 = 0
=> x(x-10) +5(x-10) = 0
=> (x-10)(x+5) = 0
x = 10 or x = -5
x can not be -5.
So x = 10
Actual marks = 10
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