Question

hadappa sabhyata ki Khoj Pramukh yogdan Dene Wale 3 ke bare mein likhen​

Answer 1

Answer:

Answer:

\huge\bold\red{➢ANSWER :-}➢ANSWER:−

➢For an A.P., let a be the first term and d be the common difference.

==>> t19 = 52, t38 = 128 …[Given]

==>>Since, tn = a + (n – 1)d

∴ t19 = a + (19 – 1)d

∴ 52 = a + 18d i.e. a + 18d = 52 …(i)

Also, t38 = a + (38 – 1)d

∴ 128 = a + 37d i.e. a + 37d = 128 …(ii)

➢ Adding equations (i) and (ii), we get

==>> a + 18d = 52

(a + 37d = 128)/(2a + 55d = 180) .....(iii)

➢ Now, Sn = n/2 [ 2a + (n - 1)d]

∴ S56 = 56/2 [ 2a + (56 - 1)d]

= 28(2a + 55d) = 28 x 180 ....[From (iii) ]

∴ S56 = 5040

∴ The sum of the first 56 terms is 5040.

Answer 2

Explanation:

jai Pubg

free fire

call of duty

fortinate

Hope less land

l hope it helps to you

please mark me as brainlist