Question

haemoglobin contains 0.33% Fe by weight.The molecular mass of haemoglobin is 67200 a.m.u.Find the no of Fe atoms present in 1 molecule of haemoglobin.( at.mass of Fe=56 a.m.u.)

pls solve this question​

Answer 1

100 g haemoglobin contains 0.33 g iron

then, 67200 g haemoglobin contains =224.44 g iron.

 

Now , 56 g iron contains=6.023 * pow(10,23) atoms of iron

then 244.44g contains =26.3*pow(10,23) atoms of iron.

 

now , 6.022*pow(10,23) molecules of haemoglobin=26.3*pow(10,23) atoms of iron

(since 67200g 0f haemoglobin =6.022*pow(10,23)moleculesof haemoglobin)

then, 1 molecule of haemoglobin contains= 4atoms of iron .