Question

Haemoglobin contains 0.33% of iron by weight. The molecular mass of haemoglobin is
approximately 67200u. Calculate the number of iron atoms present in one molecule.

Answer 1

Percentage of Fe =0.33% of 67200u of haemoglobin
Weight of Fe = (0.33/100)×67200 = 221.8
Weight of 1 atom of Fe = 55. 8
No.of atoms Fe = 221.8/55.8 = 4
Hence,4 atoms of iron is present in one molecule of haemoglobin