Haemoglobin contains 0.334% of iron by weight. The molecular weight of haemoglobin is approximately 67200. The number of iron atoms (at. wt. of Fe is 56) present in one molecule of haemoglobin are
(a) 1
(b) 6
(c) 4
(d) 2
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Ans: Percentage of Iron in Haemoglobin = 0.334 Given molecular weight of Hb = 67200 Molecular weight of Iron in Hb = (67200*0.334)/100 = 224.448 Number of atoms of Iron in Hb = (total molecular weight of Iron Hb)/ atomic weight of Iron = 224.448/56 Number of atoms of Iron in Hb = 4
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YOUR ANSWER IS OPTION C)
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