Question

hagu kemon hoi bolo

Answer 1

Answer:

△ABC is an isosceles triangle.

∴∠B=∠C=50°

∠BAC=180−50−50=80°

∠BAC=∠BDC=80°

(angles on circle by the same chord on the same side)

∠BEC is supplementary angle of ∠BAC

∴∠BEC=180−∠BAC

=180−80=100°