Chemistry, asked by Naquee, 1 year ago

hahavsbsnsjsmhsbbsjs sbznn
21 and 22

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Answered by Anonymous
10
As-Salamu-Alykum


____________


1▪

f=c/lemda

lemda=c/f

Lemda= 3×10^8/8×10^15

lemda=0.375×10^_15+8


Lemda= 0.357×10^_7

Lemda= 3.75×10^_8


Option d is correct


2▪

E=hc/lemda

lemda=hc/E

lemda= 6.62×10^_34 ×3×10^8 /3×10^_8


lemda =6.62×10^_34 ×10^16

Lemda=6.62×10^18 A°


Option d is correct


_______________


INSHALLAH it will help U


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Answered by Anonymous
13
ASSALAMUALAIKUM,

21)

h=6.63*10^-34
V=3*10^8
f = 8*10^15

E=hf
E=hc/lembda
hf=hc/lembda
f=c/lembda
f * lembda=c
lambda = c/ f

3*10^8 / 8*10^15
=0.375*10^-8
3.75*10^-8


22)

E=hc/lembda

lembda=6.64*10^-34*3*10^8 / 3*10^-8

lambda = 6.64*10^18 A°

INSHAALLAH it will help you!

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