Question

Hailstone at 0°C falls from a height of 1
km on an insulating surface converting
whole of its kinetic energy into heat.
What part of it will melt Ig = 10m/s2,
Like 330 x 10ºJkg​

Answer 1

Hailstone possesses potential energy due to is height. Let k be the fraction ice that melts.

Hence,

Potential energy=k×latent heat

mgh=kmL⇒k=

L

gh

=

330×10

3

10×1000

≈

33

1

Answer 2

Answer:

Hailstone possesses potential energy due to is height. Let k be the fraction ice that melts.

Hence,

Potential energy=k×latent heat

mgh=kmL⇒k= gh/L = 10×1000/330×10 ≈ 1/33