Question

*हल कीजिये: H.C.F. (a,b) x L.C.M. (a,b) =*

1️⃣ a/b
2️⃣ a + b
3️⃣ a - b
4️⃣ a x b​

Answer 1

Given:

H.C.F. (a,b) x L.C.M. (a,b)

To find:

H.C.F. (a,b) x L.C.M. (a,b) = ?

Solution:

Let's assume,

"a" → the first number

"b" → the second number

We know that → the product of the Highest Common Factor and the Lowest Common Multiple of two numbers is equal to the product of the two numbers.

i.e., $\bold{H.C.F. \times L.C.M. = Product \:of\:two\:numbers}$

$\implies H.C.F. \times L.C.M. = First \:Number\:\times \:Second \:Number$

substituting the values, we get

$\implies \bold{H.C.F. \times L.C.M. = a\:\times \:b}$

Thus, the correct answer is → option (4) → $\boxed{\bold{H.C.F. \times L.C.M. = a\:\times \:b}}$

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Answer 2

$Option\: \green { ( 4 ) } \: is \: correct.$

$\underline{\blue{Explanation:}}$

$If\: 'a' \: and \:'b' \: two \: positive\: numbers$

$then \: H.C.F(a,b) \times L.C.M(a,b) = a \times b$

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