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In the given figure o is the centre the angle subtended by arc BCD at the centre is 140. BC is produced to P. Determine DAB & DCB.
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Answer:
Step-by-step explanation:
Angle BAD= 1/2 Angle BOD
Angle BAD= 70°
Now, Angle BAD + Angle BCD =180°
Angle BCD= 180-70=110°
Also
Angle BCD +Angle DCP=180°
Angle DCP=70°
hharasudhan539:
pls
can u explain the theorem u used in this
Because angle subtended at the centre is twice the angle subtended at any otherpart of the circle
how did u got 70
Angle BAD= 1/2 Angle BOD
no for DCP
BCD= 180-70=110°
Angle BCD +Angle DCP=180°
linear pair
linear pair
ohk
wel come
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