half diagonal of a rectangle is 2.5 cm and one side is 4 cm find the perimeter of the rectangle
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Answered by
1
Answer: other side's length of rectangle is 3 cm
Step-by-step explanation:
Total length of one diagonal is = 2×2.5 = 5 cm
Let, other side's length of rectangle = x
By the Pythagoras theorem,
Length of Other side of rectangle = √(x^2+4^2 )
Now, √(x^2+4^2 ) = 5
, x^2 = 25 -16 = 9
, x = √9 = 3 cm
Answered by
0
Answer:
Answer: other side's length of rectangle is 3
cm
Step-by-step explanation:
Total length of one diagonal is = 2 * 2.5 = 5
cm
Let, other side's length of Je = x
By the Pythagoras theorem,
Length of Other side of rectangle = sqrt (x^ ^ 2+4^ ^ 2)
Now, mathcal V (x^ ^ 2+4^ ^ 2)=5
,*^ ^ 2=25-16=9
, x= sqrt 9=3 cm
Perimeter of rectangle:2(l+b)
=2 4+3cm
=14cm
I hope it helps please mark me as brainliest
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