Half life of a radioactive substance is 20 days what percentage of a sample will decay in 10 days
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Hey mate!!
_____________________________________________________________
→ Your answer is 29%
★ Apply formula,
The amount of radioactive mat3rial that remains after time t
A(t) = A° × 2^(-t/t.half)
where, A° is initial amount of radioactive material.
let A° =100
now, after time t
A(t) = 100 × 2(-10/20)
→ A(t) = 100 × 2^-1/2
→ A(t) = 100 × 0.707
→ A(t) = 71%
i.e REMANING = 71%
DECAYED = (100 - 71)= 29%
Hope it helps!!
#Jaihind
_____________________________________________________________
→ Your answer is 29%
★ Apply formula,
The amount of radioactive mat3rial that remains after time t
A(t) = A° × 2^(-t/t.half)
where, A° is initial amount of radioactive material.
let A° =100
now, after time t
A(t) = 100 × 2(-10/20)
→ A(t) = 100 × 2^-1/2
→ A(t) = 100 × 0.707
→ A(t) = 71%
i.e REMANING = 71%
DECAYED = (100 - 71)= 29%
Hope it helps!!
#Jaihind
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