Question

half life of a radioactive substance is 30 days number of atoms in the substance 10^12. how many disintegration of atoms per second does occur?​

Answer 1

Explanation:

rate constant =0.693/half life =0.693/30×24×3600 per sec

=2.67×10^(-7)

activity = N × rate constant =10^12×2.67×10^(-7)=2.67×10^5 atoms per sec

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