Question

half life period for first order reaction if K=5.5×10-14s-1​

Answer 1

Answer:

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Explanation:

Answer : The half life of the reaction is, 1.26\times 10^{13}s

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reaction

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reactionk = rate constant of the reaction

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reactionk = rate constant of the reactionNow put all the given values in the above relation, we get

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reactionk = rate constant of the reactionNow put all the given values in the above relation, we gett_{1/2}=\frac{0.693}{5.5\times 10^{-14}s^{-1}}

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reactionk = rate constant of the reactionNow put all the given values in the above relation, we gett_{1/2}=\frac{0.693}{5.5\times 10^{-14}s^{-1}}t_{1/2}=1.26\times 10^{13}s

Answer : The half life of the reaction is, 1.26\times 10^{13}sSolution : Given,Rate constant = 5.5\times 10^{-14}s^{-1}Relation between the rate constant and the half life of the reaction is,t_{1/2}=\frac{0.693}{k}where,t_{1/2} = half life of the reactionk = rate constant of the reactionNow put all the given values in the above relation, we gett_{1/2}=\frac{0.693}{5.5\times 10^{-14}s^{-1}}t_{1/2}=1.26\times 10^{13}sTherefore, the half life of the reaction is, 1.26\times 10^{13}s