Question

Half life period of a first order reaction is 41.09 min. calculate rate
constant in per second.
​

Answer 1

Answer:

here, half life is 41.09

so , using the formula

rate constant = 0.693 divided by half life

k=0.693/41.09

implies k=0.0168654174

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Answer 2

The rate constant of the reaction is $2.81\times 10^{-4}s^{-1}$

Explanation:

The equation used to calculate half life for first order kinetics:

$k=\frac{0.693}{t_{1/2}}$

where,

k = rate constant of the reaction

$t_{1/2}$ = half life of the reaction = 41.09 min = 2465.4 sec     (Conversion factor:  1 min = 60 second)

Putting values in above equation, we get:

$k=\frac{0.693}{2465.4s}\\\\k=2.81\times 10^{-4}s^{-1}$

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