Question

Half life period of a radioactive substance is 6h.after 24h activity is 0.01 μC,what was the initial activity
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Answer 1

Answer:

Half-life= 6 hrs. In 24 hrs. there is 24/16=4 half-life.

Answer 2

Explanation:

The activity of a radioactive substance is

R = Ro [ 1/2 ]^n ...[ R = Final number; Ro initial number ]

Here, n = number of half - lives

= t / ( T 1/2) = 24/6 = 4 ...[ T1/2 = Half life period ]

and R = 0.01 μC

So, 0.01 = Ro [ 1/2 ]^4

Ro = 0.01 × (2)^4

Ro = 0.01 × 16

Ro = 0.16 μC

∴ The Initial activity is 0.16 μC !