Half life period of n13 is 0.1 mi ntue is life time is
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For a radioactive decay with decay constant kk, the half life of the decay is
\tau=\dfrac{ln}{k}=10.1\ minutesτ=
k
ln
=10.1 minutes
\implies k=\dfrac{ln2}{10.1}\ per \ minute⟹k=
10.1
ln2
per minute
Hence mean life of the decay =\dfrac{1}{k}=\dfrac{10.1}{ln 2}\ minutes=
k
1
=
ln2
10.1
minutes =\dfrac{10.1}{0.6931}\ minutes=
0.6931
10.1
minutes
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