Chemistry, asked by nandini48001, 4 months ago

Half mole of sulphur oxide

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Answered by manas7083
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Half mole of sulphur oxide

1 \: mole \: of \: sulphuric \: oxide = 32 + (16 \times 2) = 64 \: grams

1.5 \: moles \: of \: sulphuic \: oxide= 1.5 \times 64 = 96 \: grams

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