Chemistry, asked by nandini48001, 5 months ago

Half mole of sulphur oxide

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Answered by manas7083

0

Half mole of sulphur oxide

$1 \: mole \: of \: sulphuric \: oxide = 32 + (16 \times 2) = 64 \: grams$

$1.5 \: moles \: of \: sulphuic \: oxide= 1.5 \times 64 = 96 \: grams$

$bts ❤ exo$

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