Question

half of perimeter of a triangle is 20cm. the product of (s-a)(s-b) and (s-c) is 30cm^3, where s=a+b+c, then the
area of triangle is equal to ​

Answer 1

Find area of triangle

Area of triangle is  $=20\sqrt{3}cm^2$

Step-by-step explanation:

Given, $s=20cm$ and $(s-a)(s-b)(s-c)=60cm^3$

Area of triangle $=\sqrt{s(s-a)(s-b)(s-c)}$ .........formula

So, Area of triangle $=\sqrt{20cm \cdot 60cm^3}$

$=\sqrt{1200cm^4}$

$=20\sqrt{3}cm^2$

Learn More:

• Find area of triangle:  https://brainly.com/question/12303255
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Answer 2

The area of the triangle is 24.49 cm².

Step-by-step explanation:

Given : Half of perimeter of a triangle is 20cm. The product of (s-a)(s-b) and (s-c) is 30cm³, where s=a+b+c.

To find : The  area of triangle is equal to ?

Solution :

Area of triangle is given by,

$A=\sqrt{s(s-a)(s-b)(s-c)}$

Where, s is the half of the perimeter s=20 cm

and we have given (s-a)(s-b)(s-c)= 30 cm³

Substitute the value,

$A=\sqrt{20\ cm \times 30\ cm^3}$

$A=\sqrt{600\ cm^4}$

$A=24.49\ cm^2$

Therefore, the area of the triangle is 24.49 cm².

#Learn more

Area f triangle a=20cm b=30cm c=35cm​

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