half of the perimeter of a rectangle is 51 cm. if the difference between the length ang the width is 13 cm, find the area of the rectangle
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Answer:
608
Step-by-step explanation:
Parameters = 2(l+b).
given l+b = 51.
and l-b= 13
after solving those two. l= 32 and b b = 19
so area = l*b.
= 32*19= 608
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