Question

Half the perimeter of a garden, whose length is 8 more than its width is 36m. find the dimensions of the garden and then its area.

Answer 1

Step-by-step explanation:

Let l be the length of the rectangular garden and b be the width.

Now, According to the question, the length is 4 m more than its width.i.e.

l=b+4

l-b=4....(1)

Also Given Half Parameter of the rectangle = 36 i.e.

l+b=36....(2)

Now, as we have two equations, on adding both equations, we get,

l+b+l-b=4+36

=> 2l=40

=> l=20

Putting this in equation (1),

=> 20-b=4

=> b=20-4

=> b=16

Hence Length and width of the rectangle are 20m and 16 respectively.

I hope this is the answer..

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