Math, asked by sethkartikay5, 8 months ago

half the perimeter of a rectanglular garden , whose length is 4 m more than its width 36m . find the dimensions of the garden​

Answers

Answered by squeen123
0

perimeter =2 (l+b)

half peri. 36m= (l+b)

let breadth=x

length= 4x

perimeter= 2×36

                = 72m

perimeter = 2 (l+b)

72= 2 (4+x+x)

36= 4+2x

36-4=2x

32= 2x

32/2=x

16=x

breadth=16

length= x+4=16+4=20

Answered by Niharikamishra24
1

Question:-

half the perimeter of a rectanglular garden , whose length is 4 m more than its width 36m . find the dimensions of the garden

{\pink{\underline{\underline{\bold{Answer:-}}}}}

Let the width of the garden =x meter

Then length=(x+4) meter

Half perimeter =36 m

So perimeter of garden =(2×36)=72 meters

According to the question

⇒2(l+b)=72

⇒2(x+x+4)=72

⇒2x+2x+4=74⇒4x=64⇒x=16 meters

Hence,the width of the garden =16 meters

The length of the garden =(16+4)=20 meters

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