Question

Half the perimeter of a rectangular garden is 36 m.if the length is 4 more than its width, find the dimensions of the garden​

Answer 1

$\blue{\bold{\underline{\underline{Given}}}}$

• Half the perimeter of a rectangular garden is 36 m.if the length is 4 more than its width.

$\blue{\bold{\underline{\underline{To \ Find}}}}$

• Dimensions of the garden (rectangle)

$\blue{\bold{\underline{\underline{Solution}}}}$

We know that,

➠ Perimeter of rectangle = 2(l + b)

So,

Cᴏɴᴅɪᴛɪᴏɴ -1 :-

➠ 2(l + b) /2 = 36

➠ ( l + b) = 36. --(1)

Now,

Cᴏɴᴅɪᴛɪᴏɴ -2 :-

➠ Let breadth(b) of rectangle be x m

Then,

➠ Length (l) = ( x + 4) m.

Now,

Put the above values of l and b in (1) , We get,

➭ ( l + b) = 36

➭ ( x + 4 + x) = 36

➭ 2x + 4 = 36

➭ 2x = 36 - 4

➭ 2x = 32

➭ x = 32/2

➭ x = 16

Hence,

• Length(l) = (x + 4) = 16 + 4 = 20 m

• Breadth(b) = x = 16 m

Answer 2

GIVEN

Half the perimeter of a rectangular garden is 36 m.if the length is 4 more than its width

TO FIND

Find the dimension of the garden

SOLUTION

Let the length be x and breadth be y

**According to the given condition**

✰ Half the perimeter of rectangular

garden = 36m

→ ½[2(length + breadth)] = 36

→ (x + y) = 36

→ x + y = 36 ----(i)

✰The length is 4 more than its width

→ x = y + 4

→ x - y = 4 ----(ii)

Add both the equations

→ (x + y) + (x - y) = 36 + 4

→ x + y + x - y = 40

→ 2x = 40

→ x = 40/2 = 20

Putting the value of x in equation (ii)

→ x - y = 4

→ 20 - y = 4

→ y = 20 - 4 = 16

Hence,

Required length = x = 20m

Required breadth = y = 16m