Question

half the perimeter of a rectangular Garden whose length is 4cm more than its breadth is 36 M find dimensions of the garden

Answer 1

ANSWER
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Let the length of rectangular garden be x metres

Let the breadth of rectangular garden be y.

Given half perimeter of rectangular garden is 36 m 1/2
= {2(Length + breadth) }= 36
or (x + y) = 36 x + y – 36 = 0

Also, Length is 4 m more than its width
(Length )= 4 + (Breadth) or x = 4 + (y) x – y – 4 = 0 Now,

plotting equations x + y – 36 = 0 ...(1) x – y – 4 = 0 …(2) Solving (1) x + y – 36 = 0 y = 36 – x Solving (2) x − y – 4 = 0 y = x − 4

The equations intersect at (20,16) So, the solutions of our equation is (20,16)

Length of garden = x = 20 m Breadth of garden = y = 16 m




THEREFORE

X = 20 M

Y = 16 M

Answer 2

Answer:

The length and width of the rectangular garden is 20 cm and 16 cm respectively.

Step-by-step explanation:

$\bigstar\sf{Solution :-}$

➦Half Perimeter = 36 cm

➦Length is = 4 cm more than width

➦Dimensions of the garden = ??

Let,

⟶Width of rectangle = x

⟶Length of rectangle = x + 4

⟶Half Perimeter of rectangle = 36 cm

★ According to the Question :

⟶x + (x + 4) = 36

⟶2x + 4 = 36

⟶2x = 36 - 4

⟶ 2x = 32

⟶x = 32 / 2

⟶ x = 16

Width of rectangle = 16 cm

__________________

★ Length of rectangle =

→ x + 4

→ 16 + 4

→ 20

Length of rectangle = 20 cm

_______________________

The dimensions =

Length = 20 cm

Width = 16 cm

Therefore, the length and width of the rectangular garden is 20 cm and 16 cm respectively.