half the perimeter of a rectangular garden,whose length is 4 m more than its width, is 36 m. find the dimensions of the garden
Answers
Answered by
13
Step-by-step explanation:
Given
Perimeter = 2(l+b)
Half perimeter 36m = (l+b)
let breadth = x
length = 4x
Perimeter = 2× 36
=72m
Perimeter = 2(l+b)
72= 2(4+x+x)
36= 4+2x
36-4 = 2x
32 = 2x
32/2= x
therefore, x= 16
length= x+4
= 16+4
=20.
hope it helps you
Answered by
14
Answer:
It is given that, half of the Perimeter of reactangular garden is 36 :]
So,
➦ 2(l + b)/2 = 36
➦ l + b = 36.......[Equation (i)]
Now,
Let width be x
and length be x + 4
Putting this values in equation (i) we get,
➝ l + b = 36
➝ x + x + 4 = 36
➝ 2x + 4 = 36
➝ 2x = 36 - 4
➝ 2x = 32
➝ x = 32/2
➝ x = 16 m
Therefore,
Width of reactangular garden = x = 16 m
Length of the reactangular garden = x + 4 = 16 + 4 = 20 m
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