half the perimeter of a rectangular garden,whose length is 4 m more than its width,is 36 m.find the dimensions of the garden.
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length is 20m n width 16 m
Answered by
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Hey!!!
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Let width be x m
Then,Length=4+x m
ATQ
Semi-Perimeter=36m
Then perimeter=36×2=72m
So,2(l +b)=72m
2(x+4+x)=72m
2 (2x+4)=72m
4x+8=72m
4x=72-8
x=64/4
x=16m
Hence,Width=x=16m
And,Length=4+x=4+16=20m
______________________________
Hope it helps!!! :)
______________________________
Let width be x m
Then,Length=4+x m
ATQ
Semi-Perimeter=36m
Then perimeter=36×2=72m
So,2(l +b)=72m
2(x+4+x)=72m
2 (2x+4)=72m
4x+8=72m
4x=72-8
x=64/4
x=16m
Hence,Width=x=16m
And,Length=4+x=4+16=20m
______________________________
Hope it helps!!! :)
sakshi383:
thanks
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